2x^2+20x+64=10

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Solution for 2x^2+20x+64=10 equation: 



2x^2+20x+64=10

We move all terms to the left:

2x^2+20x+64-(10)=0

We add all the numbers together, and all the variables

2x^2+20x+54=0

a = 2; b = 20; c = +54;
Δ = b2-4ac
Δ = 202-4·2·54
Δ = -32
Delta is less than zero, so there is no solution for the equation

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